2(x+1)=4[x-(2-x)]

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Solution for 2(x+1)=4[x-(2-x)] equation:


Simplifying
2(x + 1) = 4[x + -1(2 + -1x)]

Reorder the terms:
2(1 + x) = 4[x + -1(2 + -1x)]
(1 * 2 + x * 2) = 4[x + -1(2 + -1x)]
(2 + 2x) = 4[x + -1(2 + -1x)]
2 + 2x = 4[x + (2 * -1 + -1x * -1)]
2 + 2x = 4[x + (-2 + 1x)]

Reorder the terms:
2 + 2x = 4[-2 + x + 1x]

Combine like terms: x + 1x = 2x
2 + 2x = 4[-2 + 2x]
2 + 2x = [-2 * 4 + 2x * 4]
2 + 2x = [-8 + 8x]

Solving
2 + 2x = -8 + 8x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-8x' to each side of the equation.
2 + 2x + -8x = -8 + 8x + -8x

Combine like terms: 2x + -8x = -6x
2 + -6x = -8 + 8x + -8x

Combine like terms: 8x + -8x = 0
2 + -6x = -8 + 0
2 + -6x = -8

Add '-2' to each side of the equation.
2 + -2 + -6x = -8 + -2

Combine like terms: 2 + -2 = 0
0 + -6x = -8 + -2
-6x = -8 + -2

Combine like terms: -8 + -2 = -10
-6x = -10

Divide each side by '-6'.
x = 1.666666667

Simplifying
x = 1.666666667

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